python实现redis客户端单例+hbase客户端单例

当业务需要大量去连接redis或者hbase的时候，大量的连接会造成socket的大量占用，导致的结果就是服务器没有更多的端口去分配，这种情况下的最好解决方案就是实现客户端连接的单例模式，保持连接永远是同一个。说到这，可能大家没有经历过，如果在每秒钟插入4000条数据的话，这个现象就非常明显了。下面就实现下python实现操作redis+hbase单例模式，有很多改进之处，根据自己业务进行调整，可以通过打印实例的ID进行验证：

import happybaseimport redisclass _RedisMgrSingleton(type):    '''redis的单例'''    def __init__(self, name, bases, dict):        super(_RedisMgrSingleton, self).__init__(name, bases, dict)        self._instance = {}    def __call__(self, host,port,db):        if not self._instance.has_key((host,port,db)):            self._instance[(host,port,db)] = super(_RedisMgrSingleton, self).__call__(host,port,db)        return self._instance[(host,port,db )]class HbaseSingleton(type):    '''hbase的单例'''    def __init__(self, name, bases, dict):        super(HbaseSingleton, self).__init__(name, bases, dict)        self._instance = {}    def __call__(self, host,table):        if not self._instance.has_key((host,table)):            self._instance[(host,table)] = super(HbaseSingleton, self).__call__(host,table)        return self._instance[(host,table)]class RedisMgr:    "redis操作专用类"    def  __init__(self,host,port,db,max_connections=3):        "eg:  host    '192.168.2.184'   port  6379    db   14"        self.host=host        self.port=port        self.db=db        self.conn=redis.Redis(connection_pool= redis.ConnectionPool(host=host,port=port,db=db,max_connections=max_connections))    def run_redis_fun(self,funname,*args):        fun=getattr(self.conn,funname)        print args        return  fun(*args)    def pipe(self):        return self.conn.pipeline(transaction=False)    __metaclass__ = _RedisMgrSingleton      #元类实现单例class HbaseOperate(object):    def __init__(self,host,table):        self.host = host        self.table = table        self.conn = happybase.Connection(self.host)        self.table = self.conn.table(self.table)    def run(self,fun,*args):        # result =self.table.row(*args)        funname = getattr(self.table,fun)        return funname(*args)    def cells(self,column,info,version):        return self.table.cells(column,info,versions=version)    __metaclass__ = HbaseSingleton      #元类实现单例conn = HbaseOperate('xxx.xx.11.8',"history_visitor_product")result = conn.cells('chenhuachao','info:visiotr',3)print resultprint "第一次",id(conn)conn1 = HbaseOperate('xxx.xxx.11.8',"history_visitor_product")result1= conn1.cells('chenhuachao','info:visiotr',6)print result1print "第二次",id(conn1)#output['test10', 'test9', 'test97']第一次 38014896['test10', 'test9', 'test97', 'test17', 'test1345\n']第二次 38014896