MYSQL多种查询时间数据方法

本文主要给大家简单讲讲MYSQL多种查询时间数据方法，相关专业术语大家可以上网查查或者找一些相关书籍补充一下，这里就不涉猎了，我们就直奔主题吧，希望MYSQL多种查询时间数据方法这篇文章可以给大家带来一些实际帮助。

mysql查询本季度

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

SELECT *FROM表名WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

7天

SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT *FROM表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT *FROM表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月

SELECT *FROM表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

#查询本季度数据select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());#查询上季度数据select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));#查询本年数据select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());#查询上年数据select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据select name,submittime from enterprisewhere date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据select name,submittime from enterprisewhere date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select*from`user`whereDATE_FORMAT(pudate,'%Y%m')=DATE_FORMAT(CURDATE(),'%Y%m') ;select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select*fromuserwhereMONTH(FROM_UNIXTIME(pudate,'%y-%m-%d'))=MONTH(now())

select*from[user]whereYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d'))=YEAR(now())andMONTH(FROM_UNIXTIME(pudate,'%y-%m-%d'))=MONTH(now())

select*from[user]wherepudatebetween上月最后一天and下月第一天

wheredate(regdate)=curdate();

select*fromtestwhereyear(regdate)=year(now())andmonth(regdate)=month(now())andday(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )FROM `t_score`WHERE 1LIMIT 0 , 30

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