导航：首页 > 互联网科技 >

SparkSql读取hive表tblproperties异常如何解决

发表于：2025-12-01 作者：千家信息网编辑

千家信息网最后更新 2025年12月01日，本篇内容介绍了"SparkSql读取hive表tblproperties异常如何解决"的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希

千家信息网最后更新 2025年12月01日SparkSql读取hive表tblproperties异常如何解决

本篇内容介绍了"SparkSql读取hive表tblproperties异常如何解决"的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希望大家仔细阅读，能够学有所成！

问题描述

集群环境

sparksql读取Parquet 格式的hive表报错
hive的parquet表，hive和impala读取正常，使用spark-sql读取则报错

异常信息

com.fasterxml.jackson.core.JsonParseException: Unexpected end-of-input within/between Object entriesat [Source: (String)"{"type":"struct","fields":[{"name":"timestamp","type":"string","nullable":true,"metadata":{"HIVE_TYPE_STRING":"string"}},{"name":"xxx","type":"string","nullable":true,"metadata":{"HIVE_TYPE_STRING":"string"}},{"name":"xxx","type":"string","nullable":true,"; line: 1, column: 513]at com.fasterxml.jackson.core.JsonParser._constructError(JsonParser.java:1804)at com.fasterxml.jackson.core.json.ReaderBasedJsonParser._skipAfterComma2(ReaderBasedJsonParser.java:2323)at com.fasterxml.jackson.core.json.ReaderBasedJsonParser._skipComma(ReaderBasedJsonParser.java:2293)at com.fasterxml.jackson.core.json.ReaderBasedJsonParser.nextToken(ReaderBasedJsonParser.java:664)at org.json4s.jackson.JValueDeserializer.deserialize(JValueDeserializer.scala:47)at org.json4s.jackson.JValueDeserializer.deserialize(JValueDeserializer.scala:39)at org.json4s.jackson.JValueDeserializer.deserialize(JValueDeserializer.scala:32)at org.json4s.jackson.JValueDeserializer.deserialize(JValueDeserializer.scala:46)at org.json4s.jackson.JValueDeserializer.deserialize(JValueDeserializer.scala:39)at com.fasterxml.jackson.databind.ObjectReader._bindAndClose(ObjectReader.java:1611)at com.fasterxml.jackson.databind.ObjectReader.readValue(ObjectReader.java:1219)at org.json4s.jackson.JsonMethods$class.parse(JsonMethods.scala:25)at org.json4s.jackson.JsonMethods$.parse(JsonMethods.scala:55)at org.apache.spark.sql.types.DataType$.fromJson(DataType.scala:127)at org.apache.spark.sql.hive.HiveExternalCatalog$.org$apache$spark$sql$hive$HiveExternalCatalog$$getSchemaFromTableProperties(HiveExternalCatalog.scala:1382)at org.apache.spark.sql.hive.HiveExternalCatalog.restoreDataSourceTable(HiveExternalCatalog.scala:845)at org.apache.spark.sql.hive.HiveExternalCatalog.org$apache$spark$sql$hive$HiveExternalCatalog$$restoreTableMetadata(HiveExternalCatalog.scala:765)at org.apache.spark.sql.hive.HiveExternalCatalog$$anonfun$getTable$1.apply(HiveExternalCatalog.scala:734)at org.apache.spark.sql.hive.HiveExternalCatalog$$anonfun$getTable$1.apply(HiveExternalCatalog.scala:734)

问题原因

从报错来看，该hive表的tblproperites有问题，tblproperites中的json字段无法正常解析，导致SparkSql读取该表出错。 Hive和Impala在读取表的时候不会去解析tblproperites，因此正常。

问题解决