python如何采集百度搜索结果带有特定URL的链接

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#coding utf-8import requestsfrom bs4 import BeautifulSoup as bsimport refrom Queue import Queueimport threadingfrom argparse import ArgumentParserarg = ArgumentParser(description='baidu_url_collet py-script by xiaoye')arg.add_argument('keyword',help='keyword like inurl:?id=for searching sqli site')arg.add_argument('-p','--page',help='page count',dest='pagecount',type=int)arg.add_argument('-t','--thread',help='the thread_count',dest='thread_count',type=int,default=10)arg.add_argument('-o','--outfile',help='the file save result',dest='oufile',type=int,default='result.txt')result = arg.parse_args()headers = {'User-Agent':'Mozilla/5.0(windows NT 10.0 WX64;rv:50.0) Gecko/20100101 Firefox/50.0'}class Bg_url(threading.Thread):  def __init__(self,que):    threading.Thread.__init__(self)    self._que = que  def run(self):    while not self._que.empty():      URL = self._que.get()      try:        self.bd_url_collet(URL)      except Exception,e:        print(e)        pass  def bd_url_collect(self, url):    r = requests.get(url, headers=headers, timeout=3)    soup = bs(r.content, 'lxml', from_encoding='utf-8')    bqs = soup.find_all(name='a', attrs={'data-click':re.compile(r'.'), 'class':None})#获得从百度搜索出来的a标签的链接    for bq in bqs:      r = requests.get(bq['href'], headers=headers, timeout=3)#获取真实链接      if r.status_code == 200:#如果状态码为200        print r.url        with open(result.outfile, 'a') as f:          f.write(r.url + '\n')def main():  thread = []  thread_count = result.thread_count  que = Queue()  for i in range(0,(result.pagecount-1)*10,10):  que.put('https://www.baidu.com/s?wd=' + result.keyword + '&pn=' + str(i))  or i in range(thread_count):  thread.append(Bd_url(que))  for i in thread:    i.start()  for i in thread:    i.join()    if __name__ == '__main__':  main()  #执行格式python aaaaa.py "inurl:asp?id=" -p 30 -t 30

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