MySQL如何创建三张关系表

今天小编给大家分享一下MySQL如何创建三张关系表的相关知识点，内容详细，逻辑清晰，相信大部分人都还太了解这方面的知识，所以分享这篇文章给大家参考一下，希望大家阅读完这篇文章后有所收获，下面我们一起来了解一下吧。

1.创建学生表

create table tbl_stu (id int not null primary key auto_increment,name varchar(45) not null)engine=innodb default charset=utf8;

2.创建科目表

create table tbl_sub (id int not null primary key auto_increment,subject varchar(45) not null)engine=innodb default charset=utf8;

3.创建分数表

create table tbl_scores(id int not null primary key auto_increment,stu_id int,sub_id intscore decimal(5,2),constraint sco_stu foreign key(stu_id) references tbl_stu(id),constraint sco_sub foreign key(sub_id) references tbl_sub(id));

4.插入数据

insert into tbl_stu values (0,"小王");insert into tbl_stu values (0,"小宋");insert into tbl_stu values (0,"小李");insert into tbl_sub values (0,"语文");insert into tbl_sub values (0,"数学");insert into tbl_sub values (0,"英语");insert into tbl_scores values (0,1,1,90);insert into tbl_scores values (0,1,2,70);insert into tbl_scores values (0,1,3,82);insert into tbl_scores values (0,2,1,95);insert into tbl_scores values (0,2,2,70);insert into tbl_scores values (0,2,3,84);insert into tbl_scores values (0,3,1,85);insert into tbl_scores values (0,3,2,86);

5.查询全部分数

select s3.name,s2.subject,s1.score from tbl_scores as s1inner join tbl_sub as s2 on s1.sub_id = s2.idinner join tbl_stu as s3 on s1.sub_id = s3.id;

6.查询学生的平均分

select s3.name,avg(s1.score) from tbl_scores as s1inner join tbl_stu as s3 on s1.sub_id = s3.idgroup by s3.name;

7.总分排行榜

select s3.name,sum(s1.score) as s from tbl_scores as s1inner join tbl_stu as s3 on s1.stu_id = s3.idgroup by s3.name order by s desc;

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