C#怎么通过HttpWebRequest发送带有JSON Body的POST请求

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目录

• 原来的处理方式
  

• 新的方式
  

原来的处理方式

通过 GetRequestStream 来获取请求流，后把需要发送的 Json 数据写入到流中

private T PostDataViaHttpWebRequest(string baseUrl,            IReadOnlyDictionary headers,            IReadOnlyDictionary urlParas,            string requestBody=null)        {            var resuleJson = string.Empty;            try            {                var apiUrl = baseUrl;                if (urlParas != null)                    urlParas.ForEach(p =>                    {                        if (apiUrl.IndexOf("{" + p.Key + "}") > -1)                        {                            apiUrl = apiUrl.Replace("{" + p.Key + "}", p.Value);                        }                        else                        {                            apiUrl += string.Format("{0}{1}={2}", apiUrl.Contains("?") ? "&" : "?", p.Key, p.Value);                        }                    }                );                                var req = (HttpWebRequest)WebRequest.Create(apiUrl);                req.Method = "POST";                req.ContentType = "application/json";                 req.ContentLength = 0;                if (!requestBody.IsNullOrEmpty())                {                    using (var postStream = req.GetRequestStream())                    {                        var postData = Encoding.ASCII.GetBytes(requestBody);                        req.ContentLength = postData.Length;                        postStream.Write(postData, 0, postData.Length);                    }                }                if (headers != null)                {                    if (headers.Keys.Any(p => p.ToLower() == "content-type"))                        req.ContentType = headers.SingleOrDefault(p => p.Key.ToLower() == "content-type").Value;                    if (headers.Keys.Any(p => p.ToLower() == "accept"))                        req.Accept = headers.SingleOrDefault(p => p.Key.ToLower() == "accept").Value;                }                var response = (HttpWebResponse)req.GetResponse();                using(Stream stream = response.GetResponseStream())                {                    using (StreamReader reader = new StreamReader(stream, Encoding.GetEncoding("UTF-8")))                    {                        resuleJson = reader.ReadToEnd();                    }                }            }            catch (Exception ex)            {                return default(T);            }            return JsonConvert.DeserializeObject(resuleJson);        }

但是会发现，数据一直没有正常发送过去，而且代码还显得比较复杂

新的方式

这里修改一下写入 RequestStream 的方式，使用 StreamWriter 包装一下，然后直接写入需要发送的 Json 数据

private T PostDataViaHttpWebRequest(string baseUrl,            IReadOnlyDictionary headers,            IReadOnlyDictionary urlParas,            string requestBody=null)        {            var resuleJson = string.Empty;            try            {                var apiUrl = baseUrl;                if (urlParas != null)                    urlParas.ForEach(p =>                    {                        if (apiUrl.IndexOf("{" + p.Key + "}") > -1)                        {                            apiUrl = apiUrl.Replace("{" + p.Key + "}", p.Value);                        }                        else                        {                            apiUrl += string.Format("{0}{1}={2}", apiUrl.Contains("?") ? "&" : "?", p.Key, p.Value);                        }                    }                );                                var req = (HttpWebRequest)WebRequest.Create(apiUrl);                req.Method = "POST";                req.ContentType = "application/json"; //Defalt                if (!requestBody.IsNullOrEmpty())                {                    using (var postStream = new StreamWriter(req.GetRequestStream()))                    {                        postStream.Write(requestBody);                    }                }                if (headers != null)                {                    if (headers.Keys.Any(p => p.ToLower() == "content-type"))                        req.ContentType = headers.SingleOrDefault(p => p.Key.ToLower() == "content-type").Value;                    if (headers.Keys.Any(p => p.ToLower() == "accept"))                        req.Accept = headers.SingleOrDefault(p => p.Key.ToLower() == "accept").Value;                }                var response = (HttpWebResponse)req.GetResponse();                using(Stream stream = response.GetResponseStream())                {                    using (StreamReader reader = new StreamReader(stream, Encoding.GetEncoding("UTF-8")))                    {                        resuleJson = reader.ReadToEnd();                    }                }            }            catch (Exception ex)            {                return default(T);            }            return JsonConvert.DeserializeObject(resuleJson);        }

这样即可正确发送 Json 数据。

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