C++怎么实现计算24点的程序

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简单的程序：

1. 运行程序

2. 输入4个整数,比如：3 3 7 8

3. 显示所有可能的组合

代码：

#include "assert.h"#include  double operate(double num1, double num2, int op){ assert(op >= 0 && op < 4);  if(op == 0){ return num1 + num2; } else if(op == 1){ return num1 - num2; } else if(op == 2){ return num1 * num2; } else{ return num1/num2; }} int calculate(int num1, int num2, int num3, int num4){ char operators[] = "+-*/";  for(int i = 0; i < 4; i ++) { for(int j = 0; j < 4; j ++) {  for (int k = 0; k < 4; k ++)  {  double ret = operate(num1, num2, i);  ret = operate(ret, num3, j);  ret = operate(ret, num4, k);  if(abs(ret - 24) < 0.001){   printf("((%d %c %d) %c %d) %c %d = %f\n", num1, operators[i],                     num2, operators[j],       num3, operators[k],       num4, ret);  }   ret = operate(num1, num2, i);  double ret2 = operate(num3, num4, k);  ret = operate(ret, ret2, j);  if(abs(ret - 24) < 0.001){   printf("(%d %c %d) %c (%d %c %d) = %f\n", num1, operators[i],                     num2, operators[j],       num3, operators[k],       num4, ret);  }   ret = operate(num2, num3, j);  ret = operate(num1, ret, i);  ret = operate(ret, num4, k);  if(abs(ret - 24) < 0.001){   printf("(%d %c (%d %c %d)) %c %d = %f\n", num1, operators[i],                     num2, operators[j],       num3, operators[k],       num4, ret);  }   ret = operate(num2, num3, j);  ret = operate(ret, num4, k);  ret = operate(num1, ret, i);  if(abs(ret - 24) < 0.001){   printf("%d %c ((%d %c %d) %c %d) = %f\n", num1, operators[i],                    num2, operators[j],       num3, operators[k],       num4, ret);  }   ret = operate(num3, num4, k);  ret = operate(num2, ret, j);  ret = operate(num1, ret, i);  if(abs(ret - 24) < 0.001){   printf("%d %c (%d %c (%d %c %d)) = %f\n", num1, operators[i],                     num2, operators[j],       num3, operators[k],       num4, ret);  }  } } } return 0;} int main(int argc, char* argv[]){  int nums[4] = {0, 0, 0, 0}; std::cin >> nums[0] >> nums[1] >> nums[2] >> nums[3];  for (int i = 0; i < sizeof(nums)/sizeof(nums[0]); i ++) { int num1 = nums[i]; int ret = num1;   for(int j = 0; j < sizeof(nums)/sizeof(nums[0]); j ++) {  if(j == i)  continue;   int num2 = nums[j];    for(int k = 0; k < sizeof(nums)/sizeof(nums[0]); k++)  {  if( k == i || k == j)   continue;   int num3 = nums[k];   for(int l = 0; l < sizeof(nums)/sizeof(nums[0]); l ++)  {   if(l == i || l == j || l == k)   continue;    int num4 = nums[l];   calculate(num1, num2, num3, num4);  }  } } }  return 0;}

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