【C语言面试题】第1题：有符号变量和无符号变量的值得转换

#include char getChar(int x,int y){        char c;        unsigned int a = x;        (a + y > 10) ? (c = 1) : (c = 2);        return c;}int main(void){        char c1 = getChar(7,4);        char c2 = getChar(7,3);        char c3 = getChar(7,-7);        char c4 = getChar(7,-8);        //c1 = 1        printf("c1 = %d\n", c1);        //c2 = 2        printf("c2 = %d\n", c2);        /*c3 = 2 无符号类型和有符号类型作运算，        * 有符号类型会隐示转换为无符号类型        * -7转换后的无符号值加上7刚好上溢出，结果是0        */        printf("c3 = %d\n", c3);        /* c4 = 1        * -8转换后的无符号值加上7成为一个非常大的整数（差1就会溢出）        */        printf("c4 = %d\n", c4);        return 0;}