Java怎么遍历最后一个数

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Given linked list: 1->2->3->4->5, and n = 2.After removing the second node from the end, the linked list becomes 1->2->3->5.

/** * Definition for singly-linked list. * public class ListNode { *     int val; *     ListNode next; *     ListNode(int x) { val = x; } * } */public class Solution {    public ListNode removeNthFromEnd(ListNode head, int n) {        ListNode lead = head;        ListNode follow = head;        for (int i = 0; i < n; i++){            lead = lead.next;        }        if (lead == null){            head = head.next;        } else {            while (lead.next != null){                lead = lead.next;                follow = follow.next;            }            follow.next = follow.next.next;        }        return head;    }}

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