c++如何合并K个排序链表

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合并 k 个排序链表，返回合并后的排序链表。请分析和描述算法的复杂度。

示例:

输入:[  1->4->5,  1->3->4,  2->6]输出: 1->1->2->3->4->4->5->6

# Definition for singly-linked list.# class ListNode(object):#     def __init__(self, x):#         self.val = x#         self.next = Noneclass Solution(object):    def mergeKLists(self, lists):        """        :type lists: List[ListNode]        :rtype: ListNode        """        #合成一个大的listlist然后排序        lists = [x for x in lists if x]        if not lists or all([not x for x in lists]): return         head = lists.pop()                curr = head        while curr.next:            curr = curr.next                    while lists:            tmp = lists.pop()            curr.next = tmp            while tmp.next:                tmp = tmp.next            curr = tmp                if not head or not head.next: return head        return self.mergeSort(head)        def mergeSort(self, head):        if not head.next: return head        pre, slow, fast = None, head, head                while fast and fast.next:            prev, slow, fast = slow, slow.next, fast.next.next                prev.next = None        left = self.mergeSort(head)        right = self.mergeSort(slow)        return self.merge(left, right)        def merge(self, left, right):        if not left:            return right        if not right:            return left                if left.val < right.val:            res = left            res.next = self.merge(left.next, right)        else:            res = right            res.next = self.merge(left, right.next)        return res

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