怎样用Python批量爬取酷我音乐歌曲

怎样用Python批量爬取酷我音乐歌曲，针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。

本次目标

酷我音乐歌曲爬取

https://www.kugou.com/

环境介绍

• python 3.6

• pycharm

• requests

开始代码

导入工具

import requestsimport re

请求网页

headers = {    'authority': 'wwwapi.kugou.com',    'cookie': 'kg_mid=ac3836df72c523f46a85d8a5fd90fe59; kg_dfid=3ve7aQ2XyGmN0yE3uv3WcaHs; Hm_lvt_aedee6983d4cfc62f509129360d6bb3d=1600260110,1602312707; kg_dfid_collect=d41d8cd98f00b204e9800998ecf8427e; kg_mid_temp=ac3836df72c523f46a85d8a5fd90fe59; Hm_lpvt_aedee6983d4cfc62f509129360d6bb3d=1602312738',    'referer': 'https://www.kugou.com/song/',    'user-agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/81.0.4044.138 Safari/537.36',}url = 'https://www.kugou.com/yy/rank/home/1-8888.html?from=rank'response = requests.get(url=url, headers=headers)

解析网页数据

def func(url):    hashs = re.findall('"Hash":"(.*?)"', response.text, re.S)    album_ids = re.findall('"album_id":(.*?),"', response.text, re.S)    FileNames = re.findall('"FileName":"(.*?)"', response.text, re.S)    data = zip(hashs, album_ids, FileNames)    for i in data:        hash = i[0]        album_ids = i[1]        FileName = i[2].encode('utf-8').decode('unicode_escape')        # print(hash, album_ids, FileName)        download_url = 'https://wwwapi.kugou.com/yy/index.php'        params = {            'r': 'play/getdata',            'callback': 'jQuery19107150201841602037_1602314563329',            'hash': '{}'.format(hash),            'album_id': '{}'.format(album_ids),            'dfid': '3ve7aQ2XyGmN0yE3uv3WcaHs',            'mid': 'ac3836df72c523f46a85d8a5fd90fe59',            'platid': '4',            '_': '1602312793005',        }

保存数据

def download(url, title):    filename = 'C:\\Users\\Administrator\\Desktop\\新建文件夹\\' + title + '.mp3'    response = requests.get(url=url, headers=headers)    with open(filename, mode='wb') as f:        f.write(response.content)        print(title)

运行代码，效果如下图

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