C语言怎么实现简单的扫雷功能

本篇内容主要讲解"C语言怎么实现简单的扫雷功能"，感兴趣的朋友不妨来看看。本文介绍的方法操作简单快捷，实用性强。下面就让小编来带大家学习"C语言怎么实现简单的扫雷功能"吧!

下面看代码：

test.c

#define _CRT_SECURE_NO_WARNINGS#include"game.h" void test();void menu();void game();  int main(){   test(); return 0;}void menu(){ printf("*************************\n"); printf("******    1.play   ******\n"); printf("******    0.exit   ******\n"); printf("*************************\n");}void test(){ int input = 0; srand((unsigned int)time(NULL)); do {  menu();  printf("请选择: ");  scanf("%d", &input);  switch (input)  {  case 1:   printf("扫雷游戏!\n");   game();   break;  case 0:   printf("已退出游戏!\n");   break;  default:   printf("输入错误,请重新输入!\n");   break;  } } while (input);}void game(){ //雷的信息存储 //1.布置雷的信息 char mine[ROWS][COLS] = { 0 }; //11*11 //2.排查出的雷的信息 char show[ROWS][COLS] = { 0 }; //初始化 InitBoard(mine, ROWS, COLS, '0'); InitBoard(show, ROWS, COLS, '*'); //打印棋盘 DisplyBoard(mine, ROW, COL); //DisplyBoard(show, ROW, COL); //布置雷 SetMine(mine, ROW, COL); DisplyBoard(mine, ROW, COL); //扫雷 FindMine(mine, show, ROW, COL); }

game.c

#define _CRT_SECURE_NO_WARNINGS#include"game.h" //'1'-'0'=1//'3'-'0'=3int get_mine_count(char mine[ROWS][COLS], int x, int y){ return mine[x - 1][y - 1] - '0' +  mine[x][y - 1] - '0' +  mine[x + 1][y - 1] - '0' +  mine[x + 1][y] - '0' +  mine[x + 1][y + 1] - '0' +  mine[x][y + 1] - '0' +  mine[x - 1][y + 1] - '0' +  mine[x - 1][y] - '0';}  void InitBoard(char board[ROWS][COLS], int rows, int cols, char set){ int i = 0; int j = 0; for (i = 0; i < rows; i++) {  for (j = 0; j < cols; j++)  {   board[i][j] = set;  } }}  void DisplyBoard(char board[ROWS][COLS], int row, int col){ int i = 0; int j = 0; //打印列号 for (i = 0; i <= row; i++) {  printf("%d ", i); } printf("\n"); for (i = 1; i <= row; i++) {  //打印行号  printf("%d ", i);  for (j = 1; j <= col; j++)  {      printf("%c ", board[i][j]);  }    printf("\n"); }} void SetMine(char board[ROWS][COLS], int row, int col){ int count = COUNT; while (count) {  int x = rand() % row + 1;  int y = rand() % col + 1;  if (board[x][y] == '0')  {   board[x][y] = '1';   count--;  }  }} void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){ int x = 0; int y = 0; int win = 0; while (win < ROW * COL - COUNT) {  printf("请输入坐标: ");  scanf("%d%d", &x, &y);  if (x >= 1 && x <= row && y >= 1 && y <= col)  {   //坐标合法   //1.踩雷   if (mine[x][y] == '1')   {    printf("你被炸死了！！！\n");    DisplyBoard(mine, row, col);    break;   }   //不是雷   else   {    //计算x,y坐标周围有几个雷    int count = get_mine_count(mine, x, y);    show[x][y] = count + '0';    DisplyBoard(show, row, col);    win++;   }   }  else  {   printf("坐标非法，请重新输入!");  } } if (win ==  ROW * COL - COUNT) {  printf("恭喜你，排雷成功!!!\n");  DisplyBoard(mine, row, col); }}

game.h

#define ROW 9#define COL 9 #define ROWS ROW+2#define COLS COL+2 #define COUNT 80#include#include#include void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);void DisplyBoard(char board[ROWS][COLS], int row, int col);void SetMine(char board[ROWS][COLS], int row, int col);void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

到此，相信大家对"C语言怎么实现简单的扫雷功能"有了更深的了解，不妨来实际操作一番吧！这里是网站，更多相关内容可以进入相关频道进行查询，关注我们，继续学习！