Android如何判断是否Root

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为了照顾那些着急的同学，先直接给出结论：

    private static final String[] rootRelatedDirs = new String[]{            "/su", "/su/bin/su", "/sbin/su",            "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su",             "/system/xbin/su",            "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su",            "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr",            "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd",            "/system/bin/conbb", "/system/xbin/conbb"};     public static boolean hasRootPrivilege() {        boolean hasRootDir = false;        String[] rootDirs;        int dirCount = (rootDirs = rootRelatedDirs).length;        for (int i = 0; i < dirCount; ++i) {            String dir = rootDirs[i];            if ((new File(dir)).exists()) {                hasRootDir = true;                break;            }        }        return Build.TAGS != null && Build.TAGS.contains("test-keys") || hasRootDir;    }

好，接下来我们来看看到底是如何得到上述的解决方案的。首先，这是既有的判断root权限的方案，即判定两个root权限相关文件夹是否存在，以及当前账户是否具备访问其内容的权限，如果都成立，那么就认为当前账号具备root权限。然而，这种root方案在一些情况下不能很好地发挥作用。

/** * 判断Android设备是否拥有Root权限 */public class RootCheck {     private final static String TAG = "RootUtil";     public static boolean isRoot() {        String binPath = "/system/bin/su";        String xBinPath = "/system/xbin/su";        if (new File(binPath).exists() && isExecutable(binPath))            return true;        if (new File(xBinPath).exists() && isExecutable(xBinPath))            return true;        return false;    }     private static boolean isExecutable(String filePath) {        Process p = null;        try {            p = Runtime.getRuntime().exec("ls -l " + filePath);            // 获取返回内容            BufferedReader in = new BufferedReader(new InputStreamReader(p.getInputStream()));            String str = in.readLine();            Log.i(TAG, str);            if (str != null && str.length() >= 4) {                char flag = str.charAt(3);                if (flag == 's' || flag == 'x')                    return true;            }        } catch (IOException e) {            e.printStackTrace();        } finally {            if (p != null) {                p.destroy();            }        }        return false;    }}

然后我就找到了如下方案，该方案号称是腾讯bugly的root权限判断方案：

private static final String[] a = new String[]{"/su", "/su/bin/su", "/sbin/su",    "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su",     "/system/xbin/su", "/system/bin/su", "/system/sd/xbin/su",    "/system/bin/failsafe/su", "/system/bin/cufsdosck",     "/system/xbin/cufsdosck", "/system/bin/cufsmgr",     "/system/xbin/cufsmgr", "/system/bin/cufaevdd",     "/system/xbin/cufaevdd", "/system/bin/conbb",     "/system/xbin/conbb"}; public static boolean p() {  boolean var0 = false;  String[] var1 = a;  int var2 = a.length;   for(int var3 = 0; var3 < var2; ++var3) {    String var4 = var1[var3];    if ((new File(var4)).exists()) {      var0 = true;      break;    }  }   return Build.TAGS != null && Build.TAGS.contains("test-keys") || var0;}

当然，本人生性多疑，偶像是曹操曹丞相，所以自然不能人云亦云，还是实际确认一下bugly实际上是否是这样实现的，以及确保bugly在新的版本中有没有对该方案有进一步的改进。

然后我就到bugly官网，下载了其最新发布的jar包，笔者下载时最新的版本为4.4.4，然后直接解压，然后在解压的目录中搜索"test-keys"内容。

grep -r test-keys "D:\迅雷下载\Bugly_v3.4.4

最后找到了对应的文件位置和对应方法：com\tencent\bugly\crashreport\common\info\b.class

private static final String[] a = new String[]{"/su", "/su/bin/su", "/sbin/su", "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su", "/system/xbin/su", "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su", "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr", "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd", "/system/bin/conbb", "/system/xbin/conbb"};public static boolean l() {    boolean var0 = false;    String[] var1;    int var2 = (var1 = a).length;     for(int var3 = 0; var3 < var2; ++var3) {        String var4 = var1[var3];        if ((new File(var4)).exists()) {            var0 = true;            break;        }    }     return Build.TAGS != null && Build.TAGS.contains("test-keys") || var0;}

然后分析一下对应变量的意思，我们就能还原出腾讯判断Root的代码，即我们开头所贴出的解决方案：

    private static final String[] rootRelatedDirs = new String[]{            "/su", "/su/bin/su", "/sbin/su",            "/data/local/xbin/su", "/data/local/bin/su", "/data/local/su",             "/system/xbin/su",            "/system/bin/su", "/system/sd/xbin/su", "/system/bin/failsafe/su",            "/system/bin/cufsdosck", "/system/xbin/cufsdosck", "/system/bin/cufsmgr",            "/system/xbin/cufsmgr", "/system/bin/cufaevdd", "/system/xbin/cufaevdd",            "/system/bin/conbb", "/system/xbin/conbb"};     public static boolean hasRootPrivilege() {        boolean hasRootDir = false;        String[] rootDirs;        int dirCount = (rootDirs = rootRelatedDirs).length;        for (int i = 0; i < dirCount; ++i) {            String dir = rootDirs[i];            if ((new File(dir)).exists()) {                hasRootDir = true;                break;            }        }        return Build.TAGS != null && Build.TAGS.contains("test-keys") || hasRootDir;    }

以上是"Android如何判断是否Root"这篇文章的所有内容，感谢各位的阅读！相信大家都有了一定的了解，希望分享的内容对大家有所帮助，如果还想学习更多知识，欢迎关注行业资讯频道！