python怎么实现数码管显示

这篇文章主要介绍"python怎么实现数码管显示"，在日常操作中，相信很多人在python怎么实现数码管显示问题上存在疑惑，小编查阅了各式资料，整理出简单好用的操作方法，希望对大家解答"python怎么实现数码管显示"的疑惑有所帮助！接下来，请跟着小编一起来学习吧！

import pybfrom pyb import Pin #数码管a~g dp对应的开发板引脚d_Pins=[Pin(i,Pin.OUT_PP) for i in ['X1','X2','X3','X4','X5','X6','X7','X8']]#数码管位段1 2 3 4对应的引脚w_Pins=[Pin(i,Pin.OUT_PP) for i in ['Y9','Y10','Y11','Y12']] number={'0':[0,0,0,0,0,0,1,1],#0'1':[1,1,1,1,0,0,1,1],#1'2':[0,0,1,0,0,1,0,1],#2'3':[0,0,0,0,1,1,0,1],#3'4':[1,0,0,1,1,0,0,1],#4'5':[0,1,0,0,1,0,0,1],#5'6':[0,1,0,0,0,0,0,1],#6'7':[0,0,0,1,1,1,1,1],#7'8':[0,0,0,0,0,0,0,1],#8'9':[0,0,0,0,1,0,0,1],#9} def display(num,dp):    global number    count=0    for pin in d_Pins:#显示num的值        pin.value(number[num][count])        count+=1    if dp==1:        d_Pins[7].value(0)def clear():    for i in w_Pins:        i.value(0)    for i in d_Pins:        i.value(1)def showData(num):    #分割出数值的百位、千位、个位和小数位的值    d_num=num    location=d_num.find('.')    if location>0:        d_num=d_num.replace('.','')        while len(d_num)<4:            d_num='0'+d_num        for i in range(0,4):            pyb.udelay(2000)            clear()            w_Pins[3-i].value(1)            if i==location-1:                display(d_num[i],1)            else:                display(d_num[i],0)    if location<0:        for i in range(0,4):            pyb.udelay(2000)            clear()            w_Pins[3-i].value(1)            display(d_num[i],0)while True:     num='9016'    showData(num)

所需原器件

1 TPYBoard v102 一块
2 四位数码管一个
3 杜邦线若干
4 面包板一块（为了接线方便，可不用）

接线图
四位数码管引脚图

开发板与四位数码管针脚对应：

程序源代码:

import pybfrom pyb import Pin #数码管a~g dp对应的开发板引脚d_Pins=[Pin(i,Pin.OUT_PP) for i in ['X1','X2','X3','X4','X5','X6','X7','X8']]#数码管位段1 2 3 4对应的引脚w_Pins=[Pin(i,Pin.OUT_PP) for i in ['Y9','Y10','Y11','Y12']] number={'0':[0,0,0,0,0,0,1,1],#0'1':[1,1,1,1,0,0,1,1],#1'2':[0,0,1,0,0,1,0,1],#2'3':[0,0,0,0,1,1,0,1],#3'4':[1,0,0,1,1,0,0,1],#4'5':[0,1,0,0,1,0,0,1],#5'6':[0,1,0,0,0,0,0,1],#6'7':[0,0,0,1,1,1,1,1],#7'8':[0,0,0,0,0,0,0,1],#8'9':[0,0,0,0,1,0,0,1],#9} def display(num,dp):    global number    count=0    for pin in d_Pins:#显示num的值        pin.value(number[num][count])        count+=1    if dp==1:        d_Pins[7].value(0)def clear():    for i in w_Pins:        i.value(0)    for i in d_Pins:        i.value(1)def showData(num):    #分割出数值的百位、千位、个位和小数位的值    d_num=num    location=d_num.find('.')    if location>0:        d_num=d_num.replace('.','')        while len(d_num)<4:            d_num='0'+d_num        for i in range(0,4):            pyb.udelay(2000)            clear()            w_Pins[3-i].value(1)            if i==location-1:                display(d_num[i],1)            else:                display(d_num[i],0)    if location<0:        for i in range(0,4):            pyb.udelay(2000)            clear()            w_Pins[3-i].value(1)            display(d_num[i],0)while True:     num='9016'    showData(num)

到此，关于"python怎么实现数码管显示"的学习就结束了，希望能够解决大家的疑惑。理论与实践的搭配能更好的帮助大家学习，快去试试吧！若想继续学习更多相关知识，请继续关注网站，小编会继续努力为大家带来更多实用的文章！