python怎么解决有序字符数问题

from collections import OrderedDict

def ordered_count(input):   counts = OrderedDict()   for char in input:       counts[char] = counts.get(char, 0) + 1
   return list(counts.items())

from collections import OrderedDict, Counter
class OrderedCounter(Counter, OrderedDict):    pass    def ordered_count(seq):     m=OrderedCounter(seq)     return list(OrderedCounter(seq).items())

from collections import Counter
def ordered_count(input):    return list(Counter(input).items())

def abbrevName(name):    return '.'.join(w[0] for w in name.split()).upper()

abbrevName = lambda name: ".".join(e[0].upper() for e in name.split())

''.lower()''.upper()''.count()''.startswith()''.capitalize()